in-order-to-conduct-an-experiment-five-students-are-randomly-selected-from-a-class-of-20-how-many-di

Question

In  order  to conduct  an  experiment,  five  students  are  randomly selected  from  a  class  of $ 20 $.  How  many  different  groups of  five  students  are  possible?

Nandini Singh · Accepted Answer

62 asks us in order to conduct an experiment. Five students are randomly selected from a classic 20. How many different groups of five students are possible? So this is a combination since the order that the students are picked in does not matter and you have N is 20 because they say that we have 20 students and we need to pick five. So our is five. So you knew combination Funny. See Clive and we can arrive at the Formula 20 factorial 20 minus father factorial five Factorial. When you saw that out you get 15,504.

Lourence Gonhovi · Answer

or

Tony Ni · Answer

so this question nature selecting black students are the 20 students to get sick. So we&#x27;re choose were C 20 old points. So that is once the factorial punches factorial over 20 minus 15. Toil by Victoria 20. Think castle, though to be 20 times 19 15 16 overprice Pectorals sits by four times three times to turn one. So if we&#x27;re go ahead and cancel same self unplug things into your calculator. Where was the following seaquest 15 by oh, or was my answer?

Ankit Gupta · Answer

So they&#x27;re out 20 people. We have to form a group off three people. So now, in which ways we can have different combinations of people. So therefore you can have NCR, which can build in us and factorial upon r factorial and minus our factory which is 20 factorial upon three. Factory in on 17 factor. So therefore we can write in 2020 19 18 17 factorial on three. Factory A list three toe to toe with one factorial on 17 factory, we can reduce it. And so therefore we will have 1100 for TVs so from three people.

Ankit Gupta · Answer

Doritos Children Side 20 on for a committee. We need to select six students out of those 20 now, firstly, to select a chair and as secretary videos. Permutations. Since order of selection matters so select throughout off 20 we get to factorial over 20 minus two. Factorial, which is contained 2 19 into it in factorial over 20 minus two is 18 factorial. So are totally bizarre 20 into 19 which is 3 80 So we have got 3 80 ways to select a chair and a secretary for our committee now for other four members to choose other four members off committee de Villiers combination, since the order among them does not matter. So we are left with now 18% as two has already been selected for cheer person on Secretary. So twos it Ford from 18. We get it in factorial over four factorial into 18 minus four factorial. So this is it in factorial over four factorial into 14 factorial. Now this candidate in is it into 17 into 16 into 15 into 14. Factorial on four. Factory can bitterness four into three into two into one and to 14 factor last word in factory is a common term toward numerator and denominator, so we can cancel this out after calculation, we get 3006 TV&#x27;s now the total ways in which we can select two persons for chair position on secretary are 3 80 in total ways to select four other members off committee are 3060. So by using fundamental principle, off counting are totally bizarre. Post leaving will multiply the number off these in which weakens elected to person and the number of ways in which we can select the four person off the committee. So these are 3 80 and do 3060. So the daughter of a czar one million 162,000 800 So the total is to select such committee is 1,162,000.

Elizabeth Xu · Answer

So in this question here we have combination because we have 20 students to choose room and we need to choose five students for a committee and what you to the positions in the committees are the same. So that means that if we have 20 choose five our answer or a number of different ways that we can choose or 15,500 for.

Problem

From a group of $ 40 $ people, a jury of $ 1…

Problem 62 Easy Difficulty

In order to conduct an experiment, five students are randomly selected from a class of $ 20 $. How many different groups of five students are possible?

Answer

15504

Related Courses

Precalculus with Limits

Related Topics

Discussion

Top Precalculus Educators

Grace H.

Heather Z.

Kristen K.

Michael D.

Precalculus Courses

Continuity - Overview

Continuity - Example 1

Recommended Videos

Watch More Solved Questions in Chapter 9

Video Transcript

Ron Larson

Precalculus with Limits

Grace H.

Heather Z.

Kristen K.

Michael D.

Continuity - Overview

Continuity - Example 1

What do you need help with?

Textbooks

Ask a question

Courses

AI Tutor

15504

Precalculus with Limits

Grace H.

Heather Z.

Kristen K.

Michael D.

Continuity - Overview

Continuity - Example 1

Ron LarsonPrecalculus with Limits

Grace H.

Heather Z.

Kristen K.

Michael D.

Ron Larson

Precalculus with Limits