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In preparation for this problem, review Conceptual Example 7. A space traveler whose mass is 115 kg leaves earth. What are his weight and mass (a) on earth and (b) in interplanetary space where there are no nearby planetary objects?

$1.13 \times 10^{3} \mathrm{N}$

0 $\mathrm{N}$

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Cornell University

University of Michigan - Ann Arbor

Numerade Educator

Hope College

owner of the weight off the space traveler is given by his mass times. Acceleration of gravity near the surface off the earth, then in mass. Off that space traveler use 115 kilograms, so his weight is given by 115 times 9.8, which results in a weight off approximately 1113 year terms. And that's it for the first item for the next item. We are in the interplanetary space, and there are no massive bodies nearby. It means that there is no gravity acting on the space traveler in the situation. So he's in our environment where the acceleration of gravity is approximately zero. It means that his weight is also equals 20 new toes, so he's weak less when in interplanetary space.

Brazilian Center for Research in Physics