00:02
So in this problem, we calculate the electric field inside a uniformly polarized square by superposing two uniformly charged spheres whose centers are separated.
00:14
So first of all, we will calculate the field inside a uniformly charged square using the cause law, causes law.
00:24
So we get that integral e .da is equal to q divided by primitivity of re -space.
00:40
Now this equation becomes e4 pi r sphere is equal to row 4 by 3 pi r cube divided by permittivity of re -space.
00:57
So when we'll solve it for e, we'll get that e is equal to row r divided by three times primitivity of re -space.
01:06
Now, row over here is the volume charge density, and the field points in the r direction, which we combined with r2 obtain that e is equal to rr divided by 3 times primitivity of free space.
01:29
Fine, so this is the electric field, but if we superpose two spheres with opposite densities so centers are separated by distances s which point from the negative square towards the positive square so we will obtain that e is equal to e1 plus plus e2 is equal to row r1 divided by three times relativity of each space plus negative row r2 divided by three times relativity of each space so this becomes equal to row divided by three, primitivity of free space, r1 minus r2.
02:19
So this is equal to negative row s divided by three times primitiveity of free space.
02:27
So where the index 1 labels the positive sphere...