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In this question, we are required to evaluate the accumulation function f for f x is equal to integration 0 to x 1 upon 2 t plus 1 d t.
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After that, we are required to find and plot the graph for f at x is equal to 0, x is equal to 2 and x is equal to 6.
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So let's see how to solve this question.
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First of all, let's integrate the function fx, which is integration 0 to x 1 upon 2 t plus 1 d t.
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Now let's integrate this.
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So we can write the integration of 1 upon 2 t will be equals to 1 upon 2 into t squared by 2 plus the integration of 1d will be equals to t and the limits are 0 to x.
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Now substitute the limits so we get function fx is equal to x squared by 4 plus x and now substitute x is equal to 0 in order to find the value of f0.
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So we can write f0 is equal to 0 squared by 4 plus 0 which will be equals to 0 and the graph for f0 is shown below.
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So this is the graph for f0.
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Here this horizontal axis represent x and this line represents x0.
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And now let's find the value of f2, that means substitute x is equal to 2.
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So we get f2 is equal to x squared by 4 plus x...