We do this by evaluating the function at the endpoints of the interval.
We have $f(1) = 1^3 + 3*1 - 5 = -1$ and $f(2) = 2^3 + 3*2 - 5 = 7$. Since $f(1)$ is negative and $f(2)$ is positive, we know that there is a zero in the interval $(1,2)$ by the Intermediate
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