Given the rational expression \(\frac{10x^2 + 2x}{(x-1)^2(x^2+2)}\), we note that the denominator is factored as \((x-1)^2(x^2+2)\). Since \((x-1)^2\) is a repeated linear factor and \(x^2+2\) is an irreducible quadratic factor, we set up the partial fraction
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