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Hello.
00:02
So here we have this given system of three equations.
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So what we're going to do is find the determinant d of the coefficients on our variables.
00:13
So we look at the coefficients on our variables, and we take the determinant d of that corresponding matrix.
00:21
So we have the determinant.
00:23
So d here is equal to the determinant of, well, the coefficients on our first equation are 1 -2.
00:30
And 3, and then we have 3, 1, and negative 2, and then we have 2, negative 4, and 6.
00:41
Okay, so computing a 3 -by -3 determinant, we can go ahead and expand along the first row.
00:48
So if we do that, we have, well, 1 times the determinant of, well, it's minors.
00:56
We cross out the row and column here.
00:57
So we look at 1 -9 -2 -4 -6.
01:01
So the determinant there is 1 times 6, which is 6 minus negative 4 times negative 2.
01:08
That's going to be 6 minus 8, which becomes negative 2.
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So we have negative 2.
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Then we have minus, well, minus the next value here, the next value is negative 2.
01:21
If we have minus a negative 2 or plus 2 times the determinant of its minor.
01:26
So crossing out the row and column here, looking at 3 negative 2, 2.
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6...