Question
In Problems $17-26,$ solve the initial value problem.$$ \frac{d y}{d x}=8 x^{3} e^{-2 y}, \quad y(1)=0 $$
Step 1
We move all the $y$ terms to one side and all the $x$ terms to the other side. This gives us: $$ \frac{d y}{e^{-2 y}}=8 x^{3} dx $$ Show more…
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