00:01
In this problem, we're going to solve a system of equations, and the system is 5x minus y equals 21, and we have also 2x plus 3y equals negative 12.
00:19
Now, we'll go ahead and take the first equation and solve it for the y, so we'll subtract 5x off both sides to get minus y by itself, 21 minus 5x on the other side.
00:33
Now, the negative y can be divided by negative 1 on every term here to change it to y equals negative 21 plus 5x.
00:44
Now, we'll substitute this negative 21 plus 5x into the y of the other equation.
00:51
So 2x plus 3 times negative 21 plus 5x equals negative 12.
01:00
Now distribute the 3 into the parentheses, 3 times negative 21.
01:05
Is a negative 63, and three times the 5x is a minus 15x.
01:15
2x minus 15x is a negative 13x, and we can write this plus negative 63 as a minus 63.
01:24
Let's add 63 to both sides, and negative 12 plus 63, this is going to give us a 51.
01:32
When we divide by negative 13 on both sides, this is going to be, let's see here, 51...