Question
In Problems 25-54, solve each system. Use any method you wish. $\left\{\begin{aligned} x^2-x y-2 y^2 & =0 \\ x y+x+6 & =0\end{aligned}\right.$
Step 1
Factorize this equation: \[ x^2 - xy - 2y^2 = (x - 2y)(x + y) = 0 \] This gives us two possible equations: \[ x - 2y = 0 \quad \text{or} \quad x + y = 0 \] Show more…
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