Question
In Problems 25-54, solve each system. Use any method you wish.$\left\{\begin{aligned} y^2-x^2+4 & =0 \\ 2 x^2+3 y^2 & =6\end{aligned}\right.$
Step 1
Step 1: Start by rewriting the first equation in a more manageable form: \[ y^2 - x^2 + 4 = 0 \] This can be rearranged to: \[ y^2 - x^2 = -4 \] Show more…
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