Question

In Problems 35-42, find $z w$ and $\frac{z}{w}$. Leave your answers in polar form. $$ \begin{aligned} & z=\cos 120^{\circ}+i \sin 120^{\circ} \\ & w=\cos 100^{\circ}+i \sin 100^{\circ} \end{aligned} $$

   In Problems 35-42, find $z w$ and $\frac{z}{w}$. Leave your answers in polar form.
$$
\begin{aligned}
& z=\cos 120^{\circ}+i \sin 120^{\circ} \\
& w=\cos 100^{\circ}+i \sin 100^{\circ}
\end{aligned}
$$

Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry
Michael Sullivan 4th Edition
Chapter 8, Problem 36 ↓

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Both \( z \) and \( w \) are given in the polar form \( re^{i\theta} \), where \( r = 1 \) (since \( \cos^2 \theta + \sin^2 \theta = 1 \)). Thus, we can write: \[ z = e^{i 120^\circ} \] \[ w = e^{i 100^\circ} \]  Show more…

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In Problems 35-42, find $z w$ and $\frac{z}{w}$. Leave your answers in polar form. $$ \begin{aligned} & z=\cos 120^{\circ}+i \sin 120^{\circ} \\ & w=\cos 100^{\circ}+i \sin 100^{\circ} \end{aligned} $$
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Key Concepts

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Multiplication of Complex Numbers in Polar Form
When multiplying complex numbers expressed in polar form, the magnitudes (r values) are multiplied together while the angles (? values) are added. This is a direct consequence of Euler's formula and simplifies computation by converting multiplication into an operation on moduli and a summation of angles.
Polar Representation of Complex Numbers
This concept involves expressing a complex number in the form r(cos ? + i sin ?), where r is the magnitude (or modulus) of the complex number and ? is the angle (or argument) measured in radians or degrees. This representation is especially useful for multiplicative operations, as it clearly separates the scaling factor and the direction.
Division of Complex Numbers in Polar Form
Division in polar form involves dividing the magnitudes of the numbers and subtracting the angle of the divisor from the angle of the dividend. This property, like multiplication, stems from Euler's formula, and it greatly facilitates the handling of complex quotients by isolating the common operations on magnitudes and angular components.

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