Question
In Problems $41-48$, find an equation for the hyperbola described. Graph the equation.Vertices at $(1,-3)$ and $(1,1) ;$ asymptote the line $y+1=\frac{3}{2}(x-1)$
Step 1
The midpoint of these vertices gives the center of the hyperbola. The center $(h,k)$ can be calculated as follows: $h = \frac{1+1}{2} = 1$ $k = \frac{-3+1}{2} = -1$ So, the center of the hyperbola is at $(1,-1)$. Show more…
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