00:01
Alright, so we're going to use this to solve our equation on the right, so we need to set up our matrix a.
00:06
So we have 1, negative 1, positive 1, 0, negative 2, positive 1, negative 2, negative 3, 0.
00:17
Our variables are x, y, and z.
00:23
Our answers are 0, negative 1, and negative 5.
00:28
And our inverses we found in the previous section, so we just have to look for the matching matrix.
00:35
So 1, negative 1, 0, negative 2, 1.
00:39
So we've got that here, and our inverse is 3 -3 -1.
00:44
So 3 -3 -1, negative 2, 2 -negative 1, and then negative 4, 5, negative 2.
00:59
So once we have that, we can take our inverse, so 3 -3 -1, negative 2 to negative 1, negative 4, 5, negative 2.
01:11
We can multiply that by our variables.
01:18
And that should help us find our solution.
01:21
Oh, sorry, not our variables, our answers.
01:24
Oops, 01, negative 1, negative 5.
01:27
Multiplein by our variables, not going to help us out very easily.
01:31
So we end up with 3 times 0 plus negative 3 times negative 1.
01:37
Plus 1 times negative 5...