00:01
Alright, we're going to solve the following uses inverses, so writing out our matrixes, matrices.
00:06
Our a matrix would be 1, 0, 2, negative 1, 2, 3, 1, 0.
00:15
Our x matrix would be our variables, so x, y, z.
00:21
Our b matrix would be our solutions, so 2, negative 3 halves, and 2, and our inverse matrix, we would have had from our previous section.
00:35
So, matching of the 102 matrix.
00:39
So the 102 matrix has an inverse of 3 negative 2, negative 4, 3 negative 2, negative 5, and negative 1, 1 ,2.
01:06
So now that we have that, we're just going to take our inverse matrix, multiply it by our answer.
01:15
And that should give us our solution to the system.
01:22
So let's see what we get.
01:28
So three times two plus negative two times negative three halves, plus negative four times two, three times two plus negative two times negative three halves, plus negative five times two, and then negative 1 times 2 plus 1 times negative 3 halves plus 2 times 2 times 2 is 6.
02:01
Negative 2 times negative 3 is a positive 6 divided by 2 is 3 and negative 4 times 2 is 8...