0:00
Hello.
00:01
So our given equations is, again, x plus 2 plus 2z equal to 2.
00:07
Negative x plus 2y plus 3z equal to negative 3 halves.
00:11
And x minus y is equal to 2.
00:15
So from that, we get here our, given our matrix a, we get our column vector x, which is just xyz, and our matrix b is just the column vector of our constants.
00:27
Okay, so then, well, from there we get that a, we found already a inverse, right, in a prior problem.
00:40
We just take our matrix a and we put a vertical line, put the three by three identity, and then use elementary cooperations to bring the identity to the left -hand side.
00:49
What we have on the right -hand side is then the inverse, and we found that a -inverse was equal to three, negative 2 negative 4 3 negative 5 or 3 negative 2 excuse me 3 negative 2 negative 5 negative 1 1 and 2 okay so there was our our inverse matrix and then well we have we just multiply by our matrix x which is our column vector x, y, z.
01:36
So we take a inverse and we multiply by the column vector, which is two negative three halves and two.
01:51
Okay, and let's go ahead and use the dot product here, right? so again, we have a three by three matrix and a three by one matrix...