00:03
So we want to expand root 2 minus i to the sixth power.
00:09
And the easiest way to handle that is to work in terms of polar form and then bring it back.
00:14
Again, we want to leave our answer in that a plus bi form.
00:18
So we'll keep that in mind.
00:20
So root 2 minus i puts us in the fourth quadrant.
00:24
Route 2 would be my x movement.
00:27
Negative 1 would be my y movement.
00:30
In order to put this in polar form, the first thing i want to do is do the pythagory.
00:33
Theorem here.
00:34
So we have root 2 squared plus negative 1 squared and we're going to take the square root of that and that's going to come out to be the square root of 3.
00:45
So far we've got the square root of 3.
00:48
And now we have to find our angle.
00:50
And so i'm going to do the inverse tangent of negative 1 over root 2.
00:59
And that's going to come out to be about 324 .74 degrees.
01:06
Now how did i get? get that? well, first, this is going to give me a reference angle of 35 .26 degrees, and then when i put it in the fourth quadrant, i get 324 .74 .74 degrees.
01:18
So right now, we've got root 324 .74 degrees...