00:01
In this problem, we're asked to graph the system equations and then solve the system by finding their points of intersection.
00:09
So let's first go ahead and graph this.
00:11
So the first equation, y equals x squared plus one, that's the equation of a parabola where there's a plus one outside of square.
00:20
So you know your vertex is going to move up once.
00:23
So therefore, the minimum, because the number if an x square is positive, so you know it's going to open up.
00:29
So therefore the minimum is going to be 01.
00:37
And then from that, you can just go ahead and pick points.
00:42
So 1 square is 1.
00:44
1 plus 1 is 2.
00:45
So it's 1 and 2.
00:47
Same thing on the left side, negative 1, 2.
00:49
And then for 2, 2 square is 4, 4 plus 1 is 5.
00:53
So 2 and 5, negative 2 and 5.
00:57
And now you're going to connect those points together to create your parabola.
01:05
And then for the next one is a linear equation where your y intercept is a positive one.
01:11
So your graph is going to start at one.
01:14
And then your slope is one over one.
01:17
So both of them are positive.
01:18
So you're going to go up one, right one.
01:22
Up one, right one.
01:23
Up one, right one.
01:27
And now you're going to connect.
01:28
And then if you want to go to the other direction, you're going to go down one, left one, down one, left one.
01:37
So now let's connect those points together...