00:01
In this problem, we're asked to graph this system equation and solve it by finding their points of intersection.
00:08
So the first graph is a square root, and we know that we cannot have a square root negative number because that gives you non -real numbers.
00:17
So therefore, the x has to be started zero, and we know that square root zero is zero.
00:23
And then square one is one.
00:25
Squirrel four is two, and square root nine is three.
00:29
And this is the graph for the square root of the x.
00:34
And the next one we're going to graph is y equals 6 minus x, where 6 is your y intercept.
00:41
So you have to graph your y intercept.
00:43
And your slope is negative 1, so that's negative 1 over 1.
00:47
So that means you're going to go down 1 and then write 1, down 1, right 1.
00:53
So you can see that the points of intersection is located at 4 .2.
01:15
Okay, so now let's solve this and verify and verify our solution by solving this.
01:24
So because both equation equals to y, so i'm going to use substitution, then we know that the square root x is going to equal to 6 minus x.
01:33
And to get rid the square, i mean, to get rid the square root, you're going to square both sides.
01:39
So this is going to give us x equals to 6 minus x times 6 minus x.
01:47
That's what square means.
01:49
The 6 minus x is multiplied by itself.
01:53
So now you're going to foil and combine like terms...