The $x$-component of $\mathbf{v}$ can be found using the formula $v_x = \|\mathbf{v}\| \cos \alpha$, so in this case, $v_x = 5 \cos 60^\circ = \frac{5}{2}$.
The $y$-component of $\mathbf{v}$ can be found using the formula $v_y = \|\mathbf{v}\| \sin \alpha$, so
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