Question
In Problems $7-16,$ obtain the general solution to the equation.$$ \frac{d r}{d \theta}+r \tan \theta=\sec \theta $$
Step 1
It is a first order linear differential equation in the form of $\frac{dr}{d\theta} + p(\theta)r = q(\theta)$, where $p(\theta) = \tan \theta$ and $q(\theta) = \sec \theta$. Show more…
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