00:01
So in this linear programming problem, we're given our objective function as well as our constraints.
00:07
And we want to start grapping the constraints.
00:10
To start off, we know that x and y are both greater than or equal to zero, meaning that our graph lies solely in the first quadrant.
00:18
Now we want to start grapping these lines down here.
00:21
So we can rewrite this as y is less than or equal to negative x plus 10, just to make it easier for us to graph.
00:30
So our y intercept is at 10.
00:33
Our slope is negative 1, meaning that our x intercept will also be at 10.
00:40
Here we have y is greater than or equal to negative 2x plus 10.
00:47
And our y intercept is also at 10, but our x intercept would be at 5 because our slope is negative 2.
00:54
Underline would look something like this.
00:58
And now we rearrange this equation to be 2.
01:02
2y is greater than or equal to negative x plus 10.
01:06
But we can divide both sides by 2 to get y is greater than or equal to negative 1 half x plus 5.
01:15
So our y intercept would be at 5 this time.
01:19
And since we have a slope of negative 1 1 half, we know that our x intercept would be at 10.
01:25
So our feasible points would lie in this area between the the lines.
01:35
And now what we do is we want to find the coordinates of all of our corner points and list them...