00:01
In this question, we are given a sphere with radius r, and the rate of change of the radius is 30 cm per minute.
00:09
So given rate of change of the radius, means change in the radius dr over change in time dt is 30 cm per minute.
00:21
We want to find the rate of change of volume in respect to time here when t goes to two minutes.
00:27
So to find change in the volume, dv, overchange in time, d t, when t equals to two minutes.
00:39
And we are to assume that r equals zero when t equals zero.
00:45
So first of all, let's find a relationship between b and r.
00:49
We know the volume of the sphere is 4 over 3 pi r cubed.
00:55
So differentiating both sides respect to t, we have dv d t on the left.
01:08
On the right side, 4 over 3 pi is a constant, so leave it at one side.
01:12
We'll just be differentiating r -quib.
01:14
Using power rule, bring down the power 3, freeze the r, subtract one to its power, so that will be 2.
01:22
Now, don't forget to differentiate r with respect to t, so we have the r over d t...