Question
In response to the problem "Solve $x(x+1)=2 \cdot 6$," a student writes "We must have $x=2$ or $x+1=6$, which leads to $x=2$ or $x=5$ as the solutions." Is the student correct?
Step 1
The equation given is $x(x+1)=2 \cdot 6$. Simplifying the right side of the equation gives us $x(x+1)=12$. Show more…
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