00:01
Hello, so here we have that s sub -n is equal to y sub 1 plus y sub 2 and so on up to plus y sub -n, where each y -sub -i is plus 1 with probability p and negative 1 with probability 1 minus p.
00:19
So by the strong law of large numbers, we have that s -sub -n over n is going to approach e of y -sub -i.
00:28
So now we have that e of y sub i is equal to 1 p plus negative 1 times 1 minus p, which is equal to p minus 1, which is equal to p minus 1, which is equal to 2 p minus 1.
00:47
So if p is greater than 1 half, then 2p minus 1 is greater than 0, meaning that s sub n over.
00:58
Or n is going to approach here a positive number.
01:03
So therefore, s sub n eventually goes to infinity.
01:07
So after some time, the walk stays positive and can return to zero only finitely many times...