In Section 7.4 [Equations (7.41) through (7.51)], I proved Lagrange's equations for a single particle constrained to move on a two-dimensional surface. Go through the same steps to prove Lagrange's equations for a system consisting of two particles subject to various unspecified constraints. [Hint: The net force on particle 1 is the sum of the total constraint force $\mathbf{F}_{1}^{\text {cst }}$ and the total nonconstraint force $\mathbf{F}_{1},$ and likewise for particle $2 .$ The constraint forces come in many guises (the normal force of a surface, the tension force of a string tied between the particles, etc.), but it is always true that the net work done by all constraint forces in any displacement consistent with the constraints is zero $-$ this is the defining property of constraint forces. Meanwhile, we take for granted that the nonconstraint forces are derivable from a potential energy $U\left(\mathbf{r}_{1}, \mathbf{r}_{2}, t\right) ;$ that is, $\mathbf{F}_{1}=-\nabla_{1} U$ and likewise for particle $2 .$ Write down the difference $\delta S$ between the action integral for the right path given by $\mathbf{r}_{1}(t)$ and $\mathbf{r}_{2}(t)$ and any nearby wrong path given by $\mathbf{r}_{1}(t)+\epsilon_{1}(t)$ and $\mathbf{r}_{2}(t)+\epsilon_{2}(t) .$ Paralleling the steps of Section $7.4,$ you can show that $\delta S$ is given by an integral analogous to $(7.49),$ and this is zero by the defining property of constraint forces.]