Question
In silicon, the lattice constant is $5.43 \AA$. Assume a hard-sphere model. (a) Calculate the radius of a silicon atom. (b)Determine the density of silicon atoms in atoms/cm $^{3}$. (c) Use the Avogadro number to find the density of silicon.
Step 1
In an FCC lattice, the lattice constant (a) is related to the atomic radius (r) by the equation: a = 2 * sqrt(2) * r We are given the lattice constant a = 5.43 Å. We can solve for the atomic radius r: r = a / (2 * sqrt(2)) r = 5.43 Å / (2 * sqrt(2)) r ≈ 1.92 Show more…
Show all steps
Your feedback will help us improve your experience
Dominador Tan and 89 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If the lattice constant of silicon is $5.43 \AA$ A, calculate $(a)$ the distance from the center of one silicon atom to the center of its nearest neighbor, $(b)$ the number density of silicon atoms $\left(\# / \mathrm{cm}^{3}\right)$, and $(c)$ the mass density $\left(\mathrm{g} / \mathrm{cm}^{3}\right)$ of silicon.
Crystalline silicon has the same structure as diamond, with a unit cell edge length of $5.430 \AA$ A. (a) What is the Si - Si distance in this crystal? (b) Calculate the density of crystalline silicon.
Volume Density. The lattice constant of Silicon is 5.43 A (angstrom). (a) What is the volume density of Silicon? (b) What is the distance from the center of Silicon atom to the center of its nearest neighbour. [30%]
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD