In similar calorimeters, equal volumes of water and alcohol, when poured, take $100 \mathrm{~s}$. and 74 s respectively to cool from $50^{\circ} \mathrm{C}$ to $40^{\circ} \mathrm{C}$. If the thermal capacity of each calorimeter is numerically equal to volume of either liquid, then the specific heat capacity of alcohol is :
(Given: the relative density of alcohol as $0.8$ and specific heat capacity of water as $1 \mathrm{cal} / \mathrm{g} /{ }^{\circ} \mathrm{C}$ )
(a) $0.8 \mathrm{cal} / \mathrm{g}^{\circ} \mathrm{C}$
(b) $0.6 \mathrm{cal} / \mathrm{g}^{\circ} \mathrm{C}$
(c) $0.9 \mathrm{cal} / \mathrm{g}^{\circ} \mathrm{C}$
(d) $1 \mathrm{cal} / \mathrm{g}^{\circ} \mathrm{C}$