00:01
In this problem, we're considering some nucleophilic substitutions under s1 conditions.
00:06
Complete racemization does not occur in a small excess of one an antihmur is present.
00:12
And our example is what i've written here, optically pure, one broma, one phenopropine, reacts with water to form one phenopropin 1.
00:22
And we're calculating each month, each percent of the nantiumer present, using the given data, which i've written right here.
00:33
Okay, i'm going to go to a bright green for this one.
00:38
Okay, so solving first part of our problem.
00:42
So i have negative 58 and 50, 40, negative 48 and 5.
00:46
So a percent of optically pure will be 5 plus 5 divided by 48, doesn't matter, times 100 will equal about 10 .4.
01:08
Then our percent of s equal 10 .4 plus and then i'm going to have 89 .6 which is so if i do 100 minus 10 .4 i get 89 .6.
01:35
Okay, 89 .6 to better by 2 and that'll equal 55 .2 percent.
01:43
And then my r percent r would be 100 minus 100 minus 55 .2 will equal 44 .8%...