00:01
In sweet peas, we can see that the color pathway goes like this.
00:07
It's white, and then you have enzyme b from gene b to produce blue.
00:18
And then from blue, you have enzyme from gene d to produce anthocyanin, which is purple.
00:34
And so if we know a couple other things, if enzyme b is missing, you can't produce blue because you're missing this step right here.
00:47
And so those flowers will accumulate white in their petals.
00:52
If enzyme d is missing here, then you will accumulate blue pigment in the flowers.
01:06
And so you can see that depending on which enzyme is mutated, you will get a different color in the color pattern.
01:14
And so what happens when you take a parent, who is homozygous recessive for gene b and homozygous dominant for gene d.
01:26
And you breed that parent to a flower who is homozygous for gene b and homozygous recessive for gene d.
01:36
The f1, we don't even need to do a cross because there's only one possibility for the four different allele combinations.
01:44
The f1 progeny will all be heterozygous for gene b and heterozygous for gene d.
01:53
And consequently, because they have a functional enzyme at both stops in the pathway, they will be purple or anthracyanide.
02:04
Now, in the f2, if you breed two heterozygotes b, d, i'm sorry, big b, little b, big d, big, d, little d.
02:15
Crossed with the same, you expect a 933 phenotypic ratio in the f2.
02:25
And so we can start to look at this, but we need to remember our pathway as we go...