In Fig. P24.59, each capacitance C1 is 6.9, and each capacitance C2 is 4.6. (a) Compute the equi

step 1 All right, so in this problem we have this connection. So we have C1, so these are all C1, C1, C

In Fig. P24.59, each capacitance C1 is 6.9, and each...

In $\textbf{Fig. P24.59}$, each capacitance $C_1$ is $6.9\space \mu$F, and each capacitance $C_2$ is $4.6\space \mu$F. (a) Compute the equivalent capacitance of the network between points $a$ and $b$. (b) Compute the charge on each of the three capacitors nearest $a$ and $b$ when $V_{ab} = 420\space V$. (c) With 420 V across $a$ and$ $b, compute $V_{cd}.$

In $\textbf{Fig. P24.59}$, each capacitance $C_1$ is $6.9\space \mu$F, and each capacitance $C_2$ is $4.6\space \mu$F. (a) Compute the equivalent capacitance of the network between points $a$ and $b$.
(b) Compute the charge on each of the three capacitors nearest $a$ and $b$ when $V_{ab} = 420\space V$. (c) With 420 V across $a$ and$ $b, compute $V_{cd}.$

Transcript

00:01 All right, so in this problem we have this connection.

00:07 So we have c1, so these are all c1, c1, c1, c1, c1, this two are c2.

00:20 So c1, c1, c1, c1, c1, c2 and c2.

00:30 And we know that c1 is a 6 .9 microferrales.

00:35 C2 is 4 .4 .6 microfaradies, okay? so this is a point a, b, and these two are point c and d.

00:50 So in part a, we want to find out the equivalent, sorry, equivalent to capacitance of the connection.

00:57 So basically, we know that c1 is 6 .9, and these three are used the other color.

01:05 So so these three, they all see one, right? so the equivalent of these three, just the 2 .3.

01:13 And because these three, they're also in parallel with the c2.

01:18 So in that sense, we have, so the equivalent capacitance of this, of this, of this loop is simply 6 .9 microferrales over 3 plus 4 .6 microferrales, right? so this also gives you 6 .9 microfaradies.

01:45 And this 6 .5 microferrales is also, it basically has the same connection.

01:55 We have this c1 right here and we have this c1 right here and c2 right here, right? so the equivalent capacitance at this two ends, they also equal 6 .9 microferrales, all right? so, and then we're going to consider the equivalent capacitance at this ab ends.

02:15 So in essence, cab, simply equal, because these two, they are also c1, right? simple equal to 6 .9 microferrales over 3, all right? so this gives you 2 .3 microferrales.

02:34 So this is the equivalent capacitance on the 2 ends a and b.

02:40 And for part b, so we want to find out the, i want to find out the charge on this, on this one, this one, and this one, this capacity, all right? so basically, we already figured out the equivalent capacities at this two ends is also equal to 6 .9, microferrales, right? so this, so this capacitor, so i mean this connection is also equivalent to this one.

03:27 So this is abens and this is 6 .9 and this is also 6 .9, 6 .9...

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