Question

In the $(2 \times 2)$ linear systems that follow, the system (B) is obtained from (A) by performing the elementary operation $E_2+c E_1$. Prove that any solution, $x_1=s_1, x_2=s_2$, for (A) is a solution for (B). Similarly, prove that any solution, $x_1=t_1, x_2=t_2$, for (B) is a solution for (A). (A) $$ \begin{aligned} & a_{11} x_1+a_{12} x_2=b_1 \\ & a_{21} x_1+a_{22} x_2=b_2 \end{aligned} $$ (B) $$ \begin{aligned} & a_{11} x_1+a_{12} x_2=b_1 \\ & \left(a_{21}+c a_{11}\right) x_1+\left(a_{22}+c a_{12}\right) x_2=b_2+c b_1 \end{aligned} $$

    In the $(2 \times 2)$ linear systems that follow, the system (B) is obtained from (A) by performing the elementary operation $E_2+c E_1$. Prove that any solution, $x_1=s_1, x_2=s_2$, for (A) is a solution for (B). Similarly, prove that any solution, $x_1=t_1, x_2=t_2$, for (B) is a solution for (A).
(A) $$ \begin{aligned} & a_{11} x_1+a_{12} x_2=b_1 \\ & a_{21} x_1+a_{22} x_2=b_2 \end{aligned} $$
(B) $$ \begin{aligned} & a_{11} x_1+a_{12} x_2=b_1 \\ & \left(a_{21}+c a_{11}\right) x_1+\left(a_{22}+c a_{12}\right) x_2=b_2+c b_1 \end{aligned} $$
Show more…
Introduction to Linear Algebra
Introduction to Linear Algebra
Lee W. Johnson, R.… 5th Edition
Chapter 1, Problem 40 ↓

Instant Answer

verified

Step 1

The operation $E_2 + c E_1$ means that the second equation of system (A) is replaced by the sum of itself and $c$ times the first equation. This operation does not affect the first equation.  Show more…

Show all steps

lock
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
In the $(2 \times 2)$ linear systems that follow, the system (B) is obtained from (A) by performing the elementary operation $E_2+c E_1$. Prove that any solution, $x_1=s_1, x_2=s_2$, for (A) is a solution for (B). Similarly, prove that any solution, $x_1=t_1, x_2=t_2$, for (B) is a solution for (A). (A) $$ \begin{aligned} & a_{11} x_1+a_{12} x_2=b_1 \\ & a_{21} x_1+a_{22} x_2=b_2 \end{aligned} $$ (B) $$ \begin{aligned} & a_{11} x_1+a_{12} x_2=b_1 \\ & \left(a_{21}+c a_{11}\right) x_1+\left(a_{22}+c a_{12}\right) x_2=b_2+c b_1 \end{aligned} $$
Close icon
Play audio
Feedback
Powered by NumerAI
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever