Question
In the above problem, the displacement current is(A) $15 \mathrm{~A}$(B) $1.5 \mathrm{~A}$(C) $0.15 \mathrm{~A}$(D) $0.015 \mathrm{~A}$
Step 1
D.) is equal to the conduction current (I.C.). This is given by the equation: \[I.D. = I.C.\] Show more…
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Round 2
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