In the arrangement of capacitors shown in figure, each capacitor is of $9 \mu \mathrm{F}$, then the equivalent capacitance between the points $\mathrm{A}$ and $\mathrm{B}$ is
(A) $18 \mu \mathrm{F}$
(B) $9 \mu \mathrm{F}$
(C) $15 \mu \mathrm{F}$
(D) $4.5 \mathrm{Mf}$