Question
In the central Sierra Nevada of California, the percent of moisture that falls as snow rather than rain is approximated reasonably well by$$f(x)=86.3 \ln x-680$$where $x$ is the altitude in feet.(a) What percent of the moisture at 5000 ft falls as snow?(b) What percent at 7500 ft falls as snow?
Step 1
Step 1: First, we need to substitute the given altitude into the function $f(x)$ to find the percent of moisture that falls as snow at that altitude. Show more…
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In the central Sierra Nevada of California, the percent of moisture that falls as snow rather than rain is approximated by $$f(x)=86.3 \ln x-680$$ where $x$ is the altitude in feet. (a) What percent of the moisture at $5000 \mathrm{ft}$ falls as snow? (b) What percent at $7500 \mathrm{ft}$ falls as snow?
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In the central Sierra Nevada of California, the percent of moisture that falls as snow rather than rain is approximated by $$ f(x)=86.3 \ln x-680 $$ where $x$ is the altitude in feet. (a) What percent of the moisture at $5000 \mathrm{ft}$ falls as snow? (b) What percent at $7500 \mathrm{ft}$ falls as snow?
In the central Sierra Nevada (a mountain range in California), the percent of moisture that falls as snow rather than rain is approximated reasonably well by $$f(x)=86.3 \ln x-680$$ where $x$ is the altitude in feet and $f(x)$ is the percent of moisture that falls as snow. Find the percent of moisture that falls as snow at each altitude. (a) $3000 \mathrm{ft}$ (b) $4000 \mathrm{ft}$ (c) $7000 \mathrm{ft}$
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