Question
In the circuit in Fig. $\mathrm{E} 25.51$ find (a) the rate of conversion of internal (chemical) energy to electrical energy within the battery; (b) the rate of dissipation of electrical energy in the battery;(c) the rate of dissipation of electrical energy in the external resistor.
Step 1
Given that the voltage across the battery is 12 volts and the current in the circuit is 2 amperes, we can substitute these values into the equation to find the power. \[P = VI = 12V \times 2A = 24W\] Show more…
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