00:01
This problem is a matter of simplifying a circuit.
00:04
It looks frankly ugly because you have it arranged in this particular way as a big square.
00:13
But if you will track it around, as first off i'll go ahead and write up here at the top, that we need to remember that for a parallel circuit that the resistance is the reciprocal of the sum of the reciprocal.
00:31
We'll use that a couple of times in here.
00:35
But looking at this particular circuit, if you track the current as it leaves a, and you're wanting the resistance from a to b, as it leaves a, then it will go up and it will branch this way, and that is 4 kilo -ooms, and it will branch this way, and you'll have 2 kilo -ooms here and 2 kilo -ooms here.
01:02
So that's the first way that it will have to go.
01:06
And therefore, that is a parallel to parallel branches here and here.
01:13
And this one, those two are in series.
01:15
So they have a total of four.
01:17
And so my resistance for this particular loop is going to be one over, one over four, plus one over four.
01:26
Both of those being kilo -ooms.
01:28
And so i get two kilo -ooms.
01:31
So that is a resistance for that first part of the circuit.
01:36
And then to get back down to b, it comes down here...