00:01
Okay, since the opposite polarity is inserted, so now the net emf, which is the net voltage in the circuit, should be equal to 16 voltage plus 8 voltage, and this is equal to 24 voltage.
00:12
So the currents in the circuits should be equal to emf nets over total resistance, which is eventually equal to 24 over 17 ampere.
00:22
If we convert to decimal, it's equal to 1 .41 ampere.
00:26
So since the opposite polarity is inserted in this case, so now the direction of the currents should be clockwise.
00:35
So now let's take a look at a second question.
00:37
So the voltage across point ba should be equal to v1 minus ir.
00:41
B1 is the 16 voltage and the current in the circuit is 24 over 17 ampere.
00:50
And the resistor that is connected to the 16 voltage battery is having a resistance 1 .6.
00:57
Omega.
00:59
So now that's plugging back to the equation to determine the voltage across point b .a...