Question
In the circuit shown in fig the potential difference across $3 \Omega$ is.(A) $2 \mathrm{~V}$(B) $4 \mathrm{~V}$(C) $8 \mathrm{~V}$(D) $16 \mathrm{~V}$
Step 1
Step 1: According to the figure, the 2 ampere current will divide into two branches, with 1 ampere flowing through the upper branch and 1 ampere flowing through the lower branch. Show more…
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In the circuit shown in fig the potential difference across $3 \Omega$ is. (A) $2 \mathrm{~V}$ (B) $4 \mathrm{~V}$ (C) $8 \mathrm{~V}$ (D) $16 \mathrm{~V}$
In the circuit shown in figure, the potential difference between the points $A$ and $B$ will be (a) $\frac{2}{3} \mathrm{~V}$ (b) $\frac{8}{9} \mathrm{~V}$ (c) $\frac{4}{3} \mathrm{~V}$ (d) $2 \mathrm{~V}$
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Round 2
In the circuit shown, the potential difference between points $C$ and $B$ will be (A) $(8 / 9) \mathrm{V}$ (B) $(4 / 3) \mathrm{V}$ (C) $(2 / 3) \mathrm{V}$ (D) $4 \mathrm{~V}$
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