Question

In the circuit shown in Figure P5.37, assume that DC steady-state conditions exist for $t<0$. Determine at $t=0^{+}$, just after the switch is opened, the current through and volage across the inductor and the capacitor and the current through $R_{52}$ - $$ \begin{array}{ll} V_{51}=15 \mathrm{~V} & V_{52}=9 \mathrm{~V} \\ R_{51}=130 \Omega & R_{52}=290 \Omega \\ R_1=1.1 \mathrm{k} \Omega & R_2=700 \Omega \\ L=17 \mathrm{mH} & C=0.35 \mu \mathrm{~F} \end{array} $$

   In the circuit shown in Figure P5.37, assume that DC steady-state conditions exist for $t<0$. Determine at $t=0^{+}$, just after the switch is opened, the current through and volage across the inductor and the capacitor and the current through $R_{52}$ -

$$
\begin{array}{ll}
V_{51}=15 \mathrm{~V} & V_{52}=9 \mathrm{~V} \\
R_{51}=130 \Omega & R_{52}=290 \Omega \\
R_1=1.1 \mathrm{k} \Omega & R_2=700 \Omega \\
L=17 \mathrm{mH} & C=0.35 \mu \mathrm{~F}
\end{array}
$$

Principles and Applications of Electrical Engineering

Giorgio Rizzoni 4th Edition

Chapter 5, Problem 37

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Step 1

Since we're in DC steady-state conditions, the inductor acts as a short circuit (0Ω) and the capacitor acts as an open circuit (infinite resistance). Show more…

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In the circuit shown in Figure P5.37, assume that DC steady-state conditions exist for $t<0$. Determine at $t=0^{+}$, just after the switch is opened, the current through and volage across the inductor and the capacitor and the current through $R_{52}$ - $$ \begin{array}{ll} V_{51}=15 \mathrm{~V} & V_{52}=9 \mathrm{~V} \\ R_{51}=130 \Omega & R_{52}=290 \Omega \\ R_1=1.1 \mathrm{k} \Omega & R_2=700 \Omega \\ L=17 \mathrm{mH} & C=0.35 \mu \mathrm{~F} \end{array} $$

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