Question
In the circuit shown, the heat produced in the $5 \mathrm{ohm}$ resistor due to current flowing through it, is 10 calories per second. Then the heat generated in the 4 ohm resistor is:(A) 1 calorie per sec(B) 2 calorie per sec(C) 4 calorie per sec(D) 3 calorie per sec
Step 1
Given that the heat produced in the $5 \, \Omega$ resistor is $10 \, \text{calories per second}$, we can write this as: \[10 = I_1^2 \times 5\] Solving for $I_1$, we get $I_1 = \sqrt{\frac{10}{5}} = \sqrt{2}$. Show more…
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