Question
In the experiment of simple pendulum error in length of pendulum $(\ell)$ is $5 \%$ and that of $g$ is $3 \%$ then find percentage error in measurement of periodic time for pendulum(a) $4.2 \%$(b) $1.2 \%$(c) $2 \%$(d) $4 \%$
Step 1
Step 1: The time period of a simple pendulum is given by the formula: \[T = 2\pi \sqrt{\frac{l}{g}}\] where \(l\) is the length of the pendulum and \(g\) is the acceleration due to gravity. Show more…
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In a simple pendulum experiment, the maximum percentage error in the measurement of length is $2 \%$ and that in the observation of the time - period is $3 \%$. Then the maximum percentage error in determination of the acceleration due to gravity $(\mathrm{g})$ is (a) $5 \%$ (b) $6 \%$. (c) $1 \%$. (d) $8 \%$.
PHYSICAL WORLD AND MEASUREMENT
Physical World
While measuring acceleration due to gravity by a simple pendulum, a student makes a positive error of $2 \%$ in length of the pendulum and a positive error of $1 \%$ in the value of time period. The actual percentage error in the measurement of the value of $g$ will be (a) $3 \%$ (b) $4 \%$ (c) $5 \%$ (d) $0 \%$
While measuring acceleration due to gravity by a simple pendulum, a student makes a positive error of $2 \%$ in the length of the pendulum and a positive error of $1 \%$ in the value of time period. His actual percentage error in the measurement of the value of $g$ will be a. $3 \%$ b. $0 \%$ c. $4 \%$ d. $5 \%$
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