Question

In the following exercises, for each ordered pair, decide (a) is the ordered pair a solution to the equation? (b) is the point on the line? Graph can't copy $y=x-4$; A: $(0,-4)$; B: $(3,-1)$; C: $(2,2)$; D: $(1,-5)$. 

   In the following exercises, for each ordered pair, decide
(a) is the ordered pair a solution to the equation? (b) is the point on the line?
Graph can't copy

$y=x-4$;
A: $(0,-4)$; 
B: $(3,-1)$; 
C: $(2,2)$; 
D: $(1,-5)$.
Intermediate Algebra
Intermediate Algebra
Lynn Marecek 1st Edition
Chapter 3, Problem 6 ↓
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In the following exercises, for each ordered pair, decide (a) is the ordered pair a solution to the equation? (b) is the point on the line? Graph can't copy $y=x-4$; A: $(0,-4)$; B: $(3,-1)$; C: $(2,2)$; D: $(1,-5)$.
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Transcript

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00:01 In this problem, we are going to determine if each point is a solution to the equation.
00:08 So our first x, x, y ordered pair is 0, negative 4.
00:15 And we want to see if that is a solution to y equals x minus 4.
00:19 So we're going to substitute our 0 in for our x and their negative 4 in for y.
00:30 And see if that makes a true statement.
00:32 Does negative 4 equal 0 minus 4? yes, it does.
00:38 So is 0 negative 4 a solution to that equation? yes.
00:42 If we graph this equation, would 0 negative 4 be on the line on the graph? yes, it would.
00:49 If it's a solution, it is on the line.
00:54 Okay? next, we'll check 3 negative 1...
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