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In the following exercises, solve the following systems of equations by graphing. $\left\{\begin{array}{l}3 x+5 y=10 \\ y=-\frac{3}{5} x+1\end{array}\right.$

   In the following exercises, solve the following systems of equations by graphing.
$\left\{\begin{array}{l}3 x+5 y=10 \\ y=-\frac{3}{5} x+1\end{array}\right.$
Intermediate Algebra
Intermediate Algebra
Lynn Marecek 1st Edition
Chapter 4, Problem 18 ↓
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In the following exercises, solve the following systems of equations by graphing. $\left\{\begin{array}{l}3 x+5 y=10 \\ y=-\frac{3}{5} x+1\end{array}\right.$
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Transcript

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00:01 Okay, we want to solve these equations here by graphing.
00:04 In order to do that, i'm going to transform them into slope intercept form because of the slope and the y intercept.
00:11 So the first equation, i'm going to start off by subtracting 4x over.
00:15 So negative 3y is equal to a negative 4x plus 8.
00:19 And then we can divide everything by a negative 3 here.
00:22 So divide by negative 3, divide by negative 3.
00:24 So y is equal to be a positive four thirds x minus there'll be two and two thirds there.
00:35 For this equation, do the same thing.
00:37 I'll bring the 8x over.
00:38 So it'll be a negative 6y.
00:40 It's equal to a negative 8x plus 14.
00:44 Divide everything by a negative 6 here.
00:47 So i do that.
00:48 I got negative 8 divided by negative 6 is going to be a positive 4 thirds x.
00:53 Okay, 14 over negative 6.
00:55 I can divide both of those by two, and i get a negative seven thirds, which is the same as four thirds x minus.
01:07 It'll be two and one third...
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