Question

In the following exercises, solve the following systems of equations by graphing. $\left\{\begin{array}{l}3 x+y=-3 \\ 2 x+3 y=5\end{array}\right.$

   In the following exercises, solve the following systems of equations by graphing.
$\left\{\begin{array}{l}3 x+y=-3 \\ 2 x+3 y=5\end{array}\right.$
Intermediate Algebra
Intermediate Algebra
Lynn Marecek 1st Edition
Chapter 4, Problem 5 ↓
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In the following exercises, solve the following systems of equations by graphing. $\left\{\begin{array}{l}3 x+y=-3 \\ 2 x+3 y=5\end{array}\right.$
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Transcript

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00:01 So in the following exercises, we want to solve by graphing.
00:04 In order to graph both of these, it'll be probably easier to turn them both into slope intercept form, which is y equals mx plus b.
00:11 So if i do that for this one, i'm just going to subtract 3x over.
00:16 That's a negative 3x minus 3.
00:19 For this one, i have two steps to do.
00:21 I'm going to first subtract 2x over.
00:23 So it's a negative 2x and then plus 5.
00:26 And then i divide everything by 3.
00:29 So y equals negative 2 thirds x.
00:32 Plus five thirds.
00:35 So from there, if i'm going to graph these for the first one, i've got negative three and negative three x for my slope.
00:42 So i was going to start here to negative three and go one, two, three up, and one to the left.
00:47 I can go one, two, three down, one to the right, three and one, and one, two, three, and one.
00:54 So here is my first line.
00:58 That's pretty close there.
01:00 For my second line it's going to be a little bit difficult but we got five thirds for my whinercepts that's one and one third so it's about right here then negative two thirds okay so negative two thirds is going to go up to the left three so i can go up two to left one two three okay and i can see that is crossing it looks like it's going to be crossing right there if i drew my lines probably a little bit better...
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