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In the following exercises, solve the systems of equations by elimination. $\left\{\begin{array}{l}4 x+3 y=2 \\ 20 x+15 y=10\end{array}\right.$

   In the following exercises, solve the systems of equations by elimination.
$\left\{\begin{array}{l}4 x+3 y=2 \\ 20 x+15 y=10\end{array}\right.$
Intermediate Algebra
Intermediate Algebra
Lynn Marecek 1st Edition
Chapter 4, Problem 63 ↓
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In the following exercises, solve the systems of equations by elimination. $\left\{\begin{array}{l}4 x+3 y=2 \\ 20 x+15 y=10\end{array}\right.$
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Transcript

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00:01 We need to solve the following system by elimination.
00:03 So we're going to multiply our top equation by negative 5 to cancel out the xes.
00:08 We get negative 20x minus 15y is equal to negative 10.
00:13 Our bottom equation is 20x plus 15y is equal to positive 10...
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