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In the following exercises, solve the systems of equations by elimination. $\left\{\begin{array}{l}\frac{1}{3} x-y=-3 \\ \frac{2}{3} x+\frac{5}{2} y=3\end{array}\right.$

   In the following exercises, solve the systems of equations by elimination.
$\left\{\begin{array}{l}\frac{1}{3} x-y=-3 \\ \frac{2}{3} x+\frac{5}{2} y=3\end{array}\right.$
Intermediate Algebra
Intermediate Algebra
Lynn Marecek 1st Edition
Chapter 4, Problem 59 ↓
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In the following exercises, solve the systems of equations by elimination. $\left\{\begin{array}{l}\frac{1}{3} x-y=-3 \\ \frac{2}{3} x+\frac{5}{2} y=3\end{array}\right.$
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Transcript

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00:01 We need to solve the following by elimination.
00:04 So i'm going to get rid of our fraction, so we're going to multiply by the common denominator in the top one, and the common denominator in our second one.
00:12 So we get x minus 3y equals negative 9.
00:18 And then we get 4x plus 15y is equal to 18.
00:27 I'm going to multiply the top equation by 5 to cancel out our ys.
00:31 So we have 5x minus 1.
00:33 Minus 15y is equal to negative 45.
00:37 Our second equation stays 4x plus 15y is equal to 18.
00:42 Our ys cancel out.
00:45 We're left with 9x is equal to negative 45 plus 18 is negative 27...
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