Question
In the following exercises, solve the systems of equations by substitution.$$\left\{\begin{array}{l}x+y=-8 \\x-y=-6\end{array}\right.$$
Step 1
The $y$ terms will cancel out because one is positive and the other is negative. This will give us: $$x + y + x - y = -8 - 6$$ which simplifies to: $$2x = -14$$ Show more…
Show all steps
Your feedback will help us improve your experience
Edward Downes and 65 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In the following exercises, solve the systems of equations by substitution. $$ \left\{\begin{array}{l} -3 x-y=8 \\ 6 x+2 y=-16 \end{array}\right. $$
Systems of Linear Equations
Solve Systems of Equations by Elimination
In the following exercises, solve the systems of equations by substitution. $$ \left\{\begin{array}{l} y=2 x-8 \\ y=\frac{3}{5} x+6 \end{array}\right. $$
Solving Systems of Equations by Substitution
In the following exercises, solve the systems of equations by elimination. $$ \left\{\begin{array}{l} -3 x-y=8 \\ 6 x+2 y=-16 \end{array}\right. $$
Solve Systems of Linear Equations with Two Variables
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD