Question

In the following exercises, solve the systems of equations by substitution. $\left\{\begin{array}{l}2 x+y=-2 \\ 3 x-y=7\end{array}\right.$

   In the following exercises, solve the systems of equations by substitution.
$\left\{\begin{array}{l}2 x+y=-2 \\ 3 x-y=7\end{array}\right.$
Intermediate Algebra
Intermediate Algebra
Lynn Marecek 1st Edition
Chapter 4, Problem 31 ↓
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In the following exercises, solve the systems of equations by substitution. $\left\{\begin{array}{l}2 x+y=-2 \\ 3 x-y=7\end{array}\right.$
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Transcript

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00:02 Already, let's say we have the system of equations, 2x plus y equals negative 2 and 3x minus y equals 7.
00:08 And i want to solve this by substitution.
00:17 In this method, i want to substitute one equation and for the other.
00:21 So one of the things i need to do is step number one is isolate a variable.
00:27 So i'm going to choose to isolate this y here because there's no coefficient in front of this.
00:34 So why did i isolate this variable in this equation? instead of the y in the second equation.
00:41 And it has to do with the positive sign because that's a positive 1y instead of a negative 1y.
00:48 If i were to isolate this y here, i would have to divide by negative 1.
00:54 I'm looking for the least amount of work possible.
00:58 So i have 2x plus y equals negative 2.
01:05 I'm going to subtract 2x from both sides...
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