00:01
We are given that e is the region in r3, such that 0 is less than equal to x squared plus y squared, which is less than equal to 4.
00:17
We have the y is greater than are equal to 0, and that z is between 0 and the plane 3 minus x.
00:33
We are also told that f of x, y, z is given by x squared plus y squared.
00:40
So we are going to first write all this in terms of cylindrical coordinates, and then we're going to evaluate the integral of f over the region e.
00:50
So let's start with e.
00:53
The first thing we notice is that x squared plus y squared is just equal to r squared.
00:58
So if r squared is between zero and four, that means r is between zero and two.
01:06
Now, y greater than are equal to 0.
01:09
So if you look at the xy plane here, then that's this region up here.
01:15
That's y greater than equal zero.
01:16
And so you can see there that theta now varies from 0 to pi.
01:26
And then the last one, we have z is bounded above by 3 minus, and now we just replace x with our cosine theta.
01:38
And then if we want to rewrite f in terms of our insolentrical quarters, coordinates.
01:46
So x squared plus y squared is just so that's our for part a we get all everything in cylindrical coordinates.
01:58
For part b now we're going to evaluate the triple integral over e of f of x y z dv so we have 0 to pi for theta.
02:12
For r we have 0 to 2 and for z we have 0 to 3 minus our cosine theta of in this case we have r.
02:22
Times the r squared in cylindrical coordinates is just r to the third.
02:27
Dz, dr, d theta.
02:32
Now we can't break this apart yet because we can see that the integral for z depends on r and theta...